A partially full beer bottle with interior diameter is floating upright in water. A drinker takes a swig and replaces it in the water where it now floats 28 mm higher than before.
What mass of beer did the person drink?
Work:
A = area = pi*r^2, where r = (do/2) and ^ = raise to the power of
do = outer diameter of the bottle
ro = density of water = m2/v2, so mw = ro*v2, where v2 = volume of water displaced
v2 = A*dh, where dh = change in height of bottle in water
v2 = pi*(do/2)^2*(2.8 cm)
Solution:
m2 = ro*pi*(do/2)^2*(2.8 cm)