An office window has dimensions 3.4 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.96 atm, but inside the pressure is held at 1.0 atm. What net force pushes out on the window?
Work:
1 atm = 1.01 x 10^5 Pa
0.96 atm = 9.69 x 10^4 Pa
N = Newtons, m = meters, ^ = raise to the power of
force F = pressure p * area A
Inside F = (1.01 x 10^5 N/m^2)*(3.4 m x 2.1 m)
Inside F = 7.2 x 10^5 N
Outside F = (9.69 x 10^4 N/m^2)*(3.4 m x 2.1 m)
Outside F = 6.9 x 10^5 N
Solution:
Net force F = 3 x 10^4 N