Problem 2.10

Obtain the velocity distribution u = u(y) of air between two stationary plates of glass, given the shear stress Pyx = 2(Pyx)0*(y/h) and y = +/-(h/2).

Work:

Pyx = F/A, where F = shear force and A = area
Pyx = 2(Pyx)0*(y/h)
U/h = velocity gradient
F = mu*A*(U/h), where mu = viscosity and U = velocity
F = 2(Pyx)0*(y/h)*A

Solution

U = [2(Pyx)0*y/mu]

Problem posted 7/12/05 -- LAL