A fluid parcel moves along a river of shape y = x^2 + 5 and speed v = 10 m/s
Determine where acceleration is a maximum:
Solution:
Calculate the maximum acceleration:
Solution:
r = (x^2 + 5)j
x = rcosQ, where Q = theta
r = (rcosQ)^2 + 5
V = velocity = dr/dt = -2(rsinQ)
{QUESTION: Did I differentiate w.r.t. x instead of t?}
{QUESTION: Since speed v = 10 m/s, would V = v*e = (10)e be a better way to solve?
a = acceleration = dV/dt = -2(rcosQ)